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This question was previously asked in

SSC CGL Tier-II ( JSO ) 2017 Official Paper ( Held On : 22 Feb 2018 )

- 0.023
- 0.16
- 0.32
- 0.046

Option 2 : 0.16

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298865

10 Questions
10 Marks
7 Mins

Given

μ = mean = 20

σ2 = variance = 25

Formula

P(z ≤ 1) = 0.841

P(z ≤ 2) = 0.977

In normal distribution

z = (x - μ)/σ

Calculation

According to question, here x = 25

Standard deviation = √σ = 5

⇒ z = (25 - 20)/5

⇒ z = 1

⇒ P(x ≥ 25) = P(z ≥ 1)

⇒ 1 - P(z ≤ 1)

⇒ 1 - 0.841

⇒ 0.16

∴ The value of P(x ≥ 25) is 0.16

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