Home
What's new
Latest activity
Authors
Store
Latest reviews
Search products
Forums
New posts
Search forums
What's new
New posts
New listings
New products
New profile posts
Latest activity
Members
Current visitors
New profile posts
Search profile posts
Log in
Register
Cart
Cart
Loading…
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Search titles only
By:
Menu
Log in
Register
Navigation
Install the app
Install
More options
Change style
Contact us
Close Menu
Forums
SVTPerformance's Chain of Restaurants
The Blower Bistro
Keep Paxton or go with Turbo
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="97desertCobra" data-source="post: 9065326" data-attributes="member: 53488"><p>I love how my logic is flawed yet I'm the one using real math to back up my point. What have you used so far? Oh yes thats right, trust me guys I'm making that much power! You are a joke! Like stated, Johns car is using 2 turboes, both of which are larger than yours. Your logic is the one that is flawed not so smart guy!:bored: Also I never tried to compare a super charger to a turbo charger, you did and its a stupid argument. Of course boost for boost a turbo will make more, and not because the turbo flows so much more cfm, but because it doesnt have the parasitic loss from the belt spinning the blower. Lets move on.</p><p></p><p>An engine in n/a form is experiencing 14.7 pounds per square inch of pressure and makes x amount of horse power. Lets just say this engine makes 300rwhp. Now in order to double the amount of horse power that engine is producing you would have to double the amount of atmospheric pressure that it is experiencing.:idea: So now your turbo is pushing 14.7 psi and you car is making 600rwhp. </p><p></p><p>The above example is that in a perfect world with no parasitic loss, no loss from heat or friction of any kind. In the real world even the best turbo cant touch the perfect example, some can get close when they really push alot of boost in their efficiency range. So the only way for that 300rwhp engine to make more than 600rwhp with less than 14.7 psi of boost is to make more horse power n/a. How much power does your car with untouched B heads and intake make n/a do you think? 280rwhp? That would be my guess. So how is it that this magical turbo of yours can bend the laws of physics? <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite7" alt=":p" title="Stick Out Tongue :p" loading="lazy" data-shortname=":p" />op:</p></blockquote><p></p>
[QUOTE="97desertCobra, post: 9065326, member: 53488"] I love how my logic is flawed yet I'm the one using real math to back up my point. What have you used so far? Oh yes thats right, trust me guys I'm making that much power! You are a joke! Like stated, Johns car is using 2 turboes, both of which are larger than yours. Your logic is the one that is flawed not so smart guy!:bored: Also I never tried to compare a super charger to a turbo charger, you did and its a stupid argument. Of course boost for boost a turbo will make more, and not because the turbo flows so much more cfm, but because it doesnt have the parasitic loss from the belt spinning the blower. Lets move on. An engine in n/a form is experiencing 14.7 pounds per square inch of pressure and makes x amount of horse power. Lets just say this engine makes 300rwhp. Now in order to double the amount of horse power that engine is producing you would have to double the amount of atmospheric pressure that it is experiencing.:idea: So now your turbo is pushing 14.7 psi and you car is making 600rwhp. The above example is that in a perfect world with no parasitic loss, no loss from heat or friction of any kind. In the real world even the best turbo cant touch the perfect example, some can get close when they really push alot of boost in their efficiency range. So the only way for that 300rwhp engine to make more than 600rwhp with less than 14.7 psi of boost is to make more horse power n/a. How much power does your car with untouched B heads and intake make n/a do you think? 280rwhp? That would be my guess. So how is it that this magical turbo of yours can bend the laws of physics? :pop: [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
SVTPerformance's Chain of Restaurants
The Blower Bistro
Keep Paxton or go with Turbo
Top