Any mathmaticians/statisticians in the house? A twist on the birthday problem...

black4vcobra

Well-Known Member
Established Member
Premium Member
Party Liquor Posse
Joined
Feb 22, 2009
Messages
4,474
Location
Cottage Grove, WI
So I took a 400 level statistics class in college which I did pretty well in so I understand probability somewhat. One of the topics in which we had problems on was the birthday problem, essentially what are the chances that in a group of random people, 2 of them share the same birthday (assuming all days of the year are equally weighted and counting February 29 as a possible date available every year). 2 people only have a .27% chance of sharing the same birthday (1/366) x 100%.

Up the number to 4 people and the chance of 2 of them having the same birthday is ((366 x 365 x 364 x 363)/ (4 x 366)) x 100% = 1.63%. You can see that the chance of 2 people having the same birthday is not linear as the number of random people increases. In fact, by the time you get to 41 people there is a 90% chance 2 share the same birthday and with 58 people, there is a 99% chance.

So here is a real life twist, at the engineering company I work at there are 12 employees. Of the 12, 3 pairs of people share the same birthday, though none of the common birthday pairs share the same birth year. It's even more bizarre that I share a birthday, and a first name, with a coworker who is just 1 year older than myself.

What are the chances of this? I can't quite wrap my head around the necessary "and" probability calculations. Without being able to calculate the chances, it seems that the chance of this happening randomly are damn near lottery jackpot odds.

SVTP, enlighten me with your vast math/stats knowledge :beer:
 
Last edited:

black4vcobra

Well-Known Member
Established Member
Premium Member
Party Liquor Posse
Joined
Feb 22, 2009
Messages
4,474
Location
Cottage Grove, WI
Easy to explain.

Those set of people just happen to be twins.

No twins or even relation between anyone at work.

I would love to know the answer and see the explanation of how they reached their conclusion.

Me too, the best I can figure is that you take the chance that out of 12 people that there would 2 that would share the same birthday, which comes out to a probability of .166

=1- (366*365*364*363*362*361*360*359*358*357*356*355)/(366^12) = .166

Then figure that out for 10 people (since the original birthday pair doesn't count) - .116

Then figure that out for 8 people - .074

and multiply those probabilities together = .166*.116*.074 = .00142 x 100% = .142% chance.

If that is right (BIG if) then I guess it's nowhere near lottery jackpot odds as 1/.00142 = 704
 

jenkins_1120

Well-Known Member
Established Member
Joined
Sep 22, 2011
Messages
2,002
Location
Melbourne, FL
i was on a deployment we had 140 people in our unit and 3 of us had the same birthday. we never knew each other before the deployment.
 

Users who are viewing this thread



Top